Description: 从人口普查统计，已知某国新生儿母亲的年龄累计分布为N=N(t)，其中t为母亲年龄，N为新生儿的母亲年龄低于或等于t的新生儿数目。下表给出了间距为5的数据。
t 15 20 25 30 35 40 45 50
N 0 7442 26703 41635 49785 50209 50226 50230
取边界条件为N’(15)=N’(50)=0,利用三次样条插值求出15至50岁之间，每一年龄（即x=15,16,……，50）所对应的新生儿累计数目N，并绘出插值函数的图形。
-From the census statistics, a country known to the mother s age newborn cumulative distribution for N = N (t), one of t for the age of the mother, N for the newborn s mother, age less than or equal to t the number of newborns. The following table gives the distance of 5 data. t 15 20 25 30 35 40 45 50N 0 7442 26703 41635 49785 50209 50226 50230 check the boundary conditions for the N (15) = N (50) = 0, using cubic spline interpolation is obtained between the ages of 15-50, each age (that is, x = 15,16, ... ..., 50) corresponding to the number of newborns accumulated N, and mapped graphics interpolation function. Platform: |
Size: 3072 |
Author:桦华 |
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Description: 一个三次样条插值的源代码！！经过验证，好用的-A cubic spline interpolation of the source code! ! After authentication, use the Platform: |
Size: 3072 |
Author:sheldon0 |
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Description: 基于ANSYS的三维动态建模系统研究与开发
针对ANSYS软件三维数值建模的复杂性,基于三次样条插值法和趋势面分析原理,采用Borland Delphi 6.0 可视化程序设计语言开发出了三维动态自动建模系统.该系统具有操作性好、建模准确等优点,提高了建模效率,便于多方案的模拟计算. -Based on the ANSYS three-dimensional dynamic modeling system software research and development for ANSYS three-dimensional numerical modeling of the complexity, based on cubic spline interpolation method and the principle of trend surface analysis, using Borland Delphi 6.0 programming language visualization developed a three-dimensional dynamic Automatic Modeling System. The system has good operability, and accurate modeling, modeling improve the efficiency in multi-program simulation. Platform: |
Size: 416768 |
Author:Derek Hsu |
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Description: 三次样条插值，输入边界条件1: 已知两端的一阶导数 2:两端的二阶导数已知，默认:自然边界条件\n求出三次样条插值函数-Cubic spline interpolation, type 1 boundary conditions: known at both ends of the first order derivative 2: at both ends of the second derivative is known, by default: the natural boundary conditions obtained cubic spline interpolation function Platform: |
Size: 1024 |
Author:高俊华 |
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Description: 编写了龙格现象中举例的函数（1/（1+x^2））的三次样条插值图像和原图像的比较，此程序简单适用。-Prepared Runge phenomenon, for example a function of (1/(1+ X ^ 2)) of cubic spline interpolation image and the original image compared to a simple application of this procedure. Platform: |
Size: 13312 |
Author:pplovefox |
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Description: 第一、二种边界条件的三次样条插值程序，应用MATLAB编写，比较实用。-First, two kinds of boundary conditions of the cubic spline interpolation procedure, the application of MATLAB to prepare, more practical. Platform: |
Size: 1024 |
Author:谢治州 |
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Description: 比较三次样条插值和拉格朗日插值多项式对runge函数插值的效果并作图解释-Comparison of cubic spline interpolation and Lagrange interpolation polynomial interpolation of the Runge function and mapping to explain the effect of Platform: |
Size: 126976 |
Author:Liu |
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Description: 曲线的三次样条插值，在非首尾节点处具有三次光滑性质-Curve cubic spline interpolation, in both nodes with non-smooth nature of the three Platform: |
Size: 1024 |
Author:lommmmmm |
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Description: 根据所给样本数据用三种不同的方法绘制该公路并估计其长度。
分别用线性插值法、最近邻域插值法和三次样条插值法计算公路长度，并用勾股定理估计公路的长度
-According to the sample data in three different ways, the road map and estimate its length. , Respectively, by linear interpolation, nearest neighbor interpolation domain and cubic spline interpolation method to calculate the length of highways and roads with an estimated length of Pythagorean Theorem Platform: |
Size: 1024 |
Author:云天 |
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Description: 数值分析课程必备的算法：三次样条插值。有需要的同学下载-Numerical Analysis of Algorithms course required: cubic spline interpolation. Those students in need to download Platform: |
Size: 1024 |
Author:03 |
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Description: 实验一：三次样条插值（P56，例6）
一、实验目的：
1) 掌握三次样条插值的运用
2) 了解拉格朗日插值在高次上的误差
二、实验环境：Matlab6.5
三、实验内容：
1) 给定函数f(x)=1/(1+x2)，-5<=x<=5，节点xk=-5+k，(k=0,1,2…10)，用三次样条插值求S10(x)，S10’(-5)=f’(-5)，S10’(5)=f’(5)。
2）作原函数f(x)，拉格朗日插值函数Ln(x)，三次样条差值函数Sn(x)。画出三个函数的图像，比较它们的区别。
-Experiment I: cubic spline interpolation (P56, cases of 6) First, the experiment was: 1) cubic spline interpolation to master the use of 2) understanding of Lagrange interpolation in high-error second, experimental environment: Matlab6 .5 c, experimental elements: 1) a given function f (x) = 1/(1+ x2),-5 <= x <= 5, node xk =- 5+ k, (k = 0,1,2 ... 10), using cubic spline interpolation for S10 (x), S10 (-5) = f (-5), S10 (5) = f (5). 2) for the original function f (x), the Lagrange interpolation function Ln (x), cubic spline difference function Sn (x). Draw the three functions of images, compare the difference between them. Platform: |
Size: 44032 |
Author:TNG |
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Description: 三次样条插值法，是运用的数值计算方法的算法实现的-Cubic spline interpolation method is the use of numerical method of implementation of the algorithm Platform: |
Size: 366592 |
Author:kevin |
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